3=(2y+5)+4y=5

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Solution for 3=(2y+5)+4y=5 equation: 



3=(2y+5)+4y=5

We move all terms to the left:

3-((2y+5)+4y)=0



We calculate terms in parentheses: -((2y+5)+4y), so:

(2y+5)+4y

We add all the numbers together, and all the variables

4y+(2y+5)

We get rid of parentheses

4y+2y+5

We add all the numbers together, and all the variables

6y+5

Back to the equation:

-(6y+5)



We get rid of parentheses

-6y-5+3=0

We add all the numbers together, and all the variables

-6y-2=0

We move all terms containing y to the left, all other terms to the right

-6y=2

y=2/-6

y=-1/3

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