3=(2y+5)+4y=5

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Solution for 3=(2y+5)+4y=5 equation:



3=(2y+5)+4y=5
We move all terms to the left:
3-((2y+5)+4y)=0
We calculate terms in parentheses: -((2y+5)+4y), so:
(2y+5)+4y
We add all the numbers together, and all the variables
4y+(2y+5)
We get rid of parentheses
4y+2y+5
We add all the numbers together, and all the variables
6y+5
Back to the equation:
-(6y+5)
We get rid of parentheses
-6y-5+3=0
We add all the numbers together, and all the variables
-6y-2=0
We move all terms containing y to the left, all other terms to the right
-6y=2
y=2/-6
y=-1/3

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