3=(c-5)/2

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Solution for 3=(c-5)/2 equation:



3=(c-5)/2
We move all terms to the left:
3-((c-5)/2)=0
We multiply all the terms by the denominator
-((c-5)+3*2)=0
We calculate terms in parentheses: -((c-5)+3*2), so:
(c-5)+3*2
We add all the numbers together, and all the variables
(c-5)+6
We get rid of parentheses
c-5+6
We add all the numbers together, and all the variables
c+1
Back to the equation:
-(c+1)
We get rid of parentheses
-c-1=0
We add all the numbers together, and all the variables
-1c-1=0
We move all terms containing c to the left, all other terms to the right
-c=1
c=1/-1
c=-1

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