3=(q+4/3)=2

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Solution for 3=(q+4/3)=2 equation: 



3=(q+4/3)=2

We move all terms to the left:

3-((q+4/3))=0

We add all the numbers together, and all the variables

-((+q+4/3))+3=0

We multiply all the terms by the denominator


-((+q+4+3*3))=0



We calculate terms in parentheses: -((+q+4+3*3)), so:

(+q+4+3*3)

We add all the numbers together, and all the variables

(q+13)

We get rid of parentheses

q+13

Back to the equation:

-(q+13)



We get rid of parentheses

-q-13=0

We add all the numbers together, and all the variables

-1q-13=0

We move all terms containing q to the left, all other terms to the right

-q=13

q=13/-1

q=-13

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