3=(q+4/3)=2

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Solution for 3=(q+4/3)=2 equation:



3=(q+4/3)=2
We move all terms to the left:
3-((q+4/3))=0
We add all the numbers together, and all the variables
-((+q+4/3))+3=0
We multiply all the terms by the denominator
-((+q+4+3*3))=0
We calculate terms in parentheses: -((+q+4+3*3)), so:
(+q+4+3*3)
We add all the numbers together, and all the variables
(q+13)
We get rid of parentheses
q+13
Back to the equation:
-(q+13)
We get rid of parentheses
-q-13=0
We add all the numbers together, and all the variables
-1q-13=0
We move all terms containing q to the left, all other terms to the right
-q=13
q=13/-1
q=-13

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