3=(x-2)+2x+10

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Solution for 3=(x-2)+2x+10 equation: 



3=(x-2)+2x+10

We move all terms to the left:

3-((x-2)+2x+10)=0



We calculate terms in parentheses: -((x-2)+2x+10), so:

(x-2)+2x+10

We add all the numbers together, and all the variables

2x+(x-2)+10

We get rid of parentheses

2x+x-2+10

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We get rid of parentheses

-3x-8+3=0

We add all the numbers together, and all the variables

-3x-5=0

We move all terms containing x to the left, all other terms to the right

-3x=5

x=5/-3

x=-1+2/3

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