3=-1/2(-5)+b

Solution for 3=-1/2(-5)+b equation:

3=-1/2(-5)+b

We move all terms to the left:

3-(-1/2(-5)+b)=0


Domain of the equation: 2(-5)+b)!=0

b∈R


We multiply all the terms by the denominator


-(-1+3*2(-5)+b)=0


We calculate terms in parentheses: -(-1+3*2(-5)+b), so:

-1+3*2(-5)+b

determiningTheFunctionDomain
b-1+3*2(-5)

We add all the numbers together, and all the variables

b-31

Back to the equation:

-(b-31)


We get rid of parentheses

-b+31=0

We add all the numbers together, and all the variables

-1b+31=0

We move all terms containing b to the left, all other terms to the right

-b=-31

b=-31/-1

b=+31