3=-1/3(10)+b

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Solution for 3=-1/3(10)+b equation: 



3=-1/3(10)+b

We move all terms to the left:

3-(-1/3(10)+b)=0



Domain of the equation: 310+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-310

b!=-310/1

b!=-310

b∈R



We add all the numbers together, and all the variables

-(+b-1/310)+3=0

We get rid of parentheses

-b+3+1/310=0

We multiply all the terms by the denominator


-b*310+1+3*310=0

We add all the numbers together, and all the variables

-b*310+931=0

Wy multiply elements

-310b+931=0

We move all terms containing b to the left, all other terms to the right

-310b=-931

b=-931/-310

b=3+1/310

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