3=-3(6-2m)+2(m-5)

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Solution for 3=-3(6-2m)+2(m-5) equation: 



3=-3(6-2m)+2(m-5)

We move all terms to the left:

3-(-3(6-2m)+2(m-5))=0

We add all the numbers together, and all the variables

-(-3(-2m+6)+2(m-5))+3=0



We calculate terms in parentheses: -(-3(-2m+6)+2(m-5)), so:

-3(-2m+6)+2(m-5)

We multiply parentheses

6m+2m-18-10

We add all the numbers together, and all the variables

8m-28

Back to the equation:

-(8m-28)



We get rid of parentheses

-8m+28+3=0

We add all the numbers together, and all the variables

-8m+31=0

We move all terms containing m to the left, all other terms to the right

-8m=-31

m=-31/-8

m=3+7/8

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