3=-3(y-5)-2(y+1/3)

Solution for 3=-3(y-5)-2(y+1/3) equation:

3=-3(y-5)-2(y+1/3)

We move all terms to the left:

3-(-3(y-5)-2(y+1/3))=0

We add all the numbers together, and all the variables

-(-3(y-5)-2(+y+1/3))+3=0

We multiply all the terms by the denominator


-(-3(y-5)-2(+y+1+3*3))=0


We calculate terms in parentheses: -(-3(y-5)-2(+y+1+3*3)), so:

-3(y-5)-2(+y+1+3*3)

We add all the numbers together, and all the variables

-3(y-5)-2(y+10)

We multiply parentheses

-3y-2y+15-20

We add all the numbers together, and all the variables

-5y-5

Back to the equation:

-(-5y-5)


We get rid of parentheses

5y+5=0

We move all terms containing y to the left, all other terms to the right

5y=-5

y=-5/5

y=-1