3=-36x-(7/x)-6

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Solution for 3=-36x-(7/x)-6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3 = -36*x-(7/x)-6 // + -36*x-(7/x)-6

7/x-(-36*x)+3+6 = 0

36*x+7/x+3+6 = 0

36*x^1+7*x^-1+9*x^0 = 0

(36*x^2+9*x^1+7*x^0)/(x^1) = 0 // * x^2

x^1*(36*x^2+9*x^1+7*x^0) = 0

x^1

36*x^2+9*x+7 = 0

36*x^2+9*x+7 = 0

DELTA = 9^2-(4*7*36)

DELTA = -927

DELTA < 0

x in { } 

x belongs to the empty set

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