3=-4/2(2)+b

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Solution for 3=-4/2(2)+b equation: 



3=-4/2(2)+b

We move all terms to the left:

3-(-4/2(2)+b)=0



Domain of the equation: 22+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-22

b!=-22/1

b!=-22

b∈R



We add all the numbers together, and all the variables

-(+b-4/22)+3=0

We get rid of parentheses

-b+3+4/22=0

We multiply all the terms by the denominator


-b*22+4+3*22=0

We add all the numbers together, and all the variables

-b*22+70=0

Wy multiply elements

-22b+70=0

We move all terms containing b to the left, all other terms to the right

-22b=-70

b=-70/-22

b=3+2/11

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