3=-4/2(2)+b

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Solution for 3=-4/2(2)+b equation:



3=-4/2(2)+b
We move all terms to the left:
3-(-4/2(2)+b)=0
Domain of the equation: 22+b)!=0
We move all terms containing b to the left, all other terms to the right
b)!=-22
b!=-22/1
b!=-22
b∈R
We add all the numbers together, and all the variables
-(+b-4/22)+3=0
We get rid of parentheses
-b+3+4/22=0
We multiply all the terms by the denominator
-b*22+4+3*22=0
We add all the numbers together, and all the variables
-b*22+70=0
Wy multiply elements
-22b+70=0
We move all terms containing b to the left, all other terms to the right
-22b=-70
b=-70/-22
b=3+2/11

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