3=-9-(-10+z)

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Solution for 3=-9-(-10+z) equation: 



3=-9-(-10+z)

We move all terms to the left:

3-(-9-(-10+z))=0

We add all the numbers together, and all the variables

-(-9-(z-10))+3=0



We calculate terms in parentheses: -(-9-(z-10)), so:

-9-(z-10)

determiningTheFunctionDomain
-(z-10)-9

We get rid of parentheses

-z+10-9

We add all the numbers together, and all the variables

-1z+1

Back to the equation:

-(-1z+1)



We get rid of parentheses

1z-1+3=0

We add all the numbers together, and all the variables

z+2=0

We move all terms containing z to the left, all other terms to the right

z=-2

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