3=1/2(3x+1)(x+8)

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Solution for 3=1/2(3x+1)(x+8) equation: 



3=1/2(3x+1)(x+8)

We move all terms to the left:

3-(1/2(3x+1)(x+8))=0



Domain of the equation: 2(3x+1)(x+8))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+24x+x+8))+3=0

We multiply all the terms by the denominator


-(1+3*2(+3x^2+24x+x+8))=0



We calculate terms in parentheses: -(1+3*2(+3x^2+24x+x+8)), so:

1+3*2(+3x^2+24x+x+8)

determiningTheFunctionDomain
3*2(+3x^2+24x+x+8)+1

Wy multiply elements

6x(++1

We use the square of the difference formula

6x(+1

Back to the equation:

-(6x(+1)



We add all the numbers together, and all the variables

-(6x1=0

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