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3=1/3(-6)+b
We move all terms to the left:
3-(1/3(-6)+b)=0
Domain of the equation: 3(-6)+b)!=0We multiply all the terms by the denominator
b∈R
-(1+3*3(-6)+b)=0
We calculate terms in parentheses: -(1+3*3(-6)+b), so:We get rid of parentheses
1+3*3(-6)+b
determiningTheFunctionDomain b+1+3*3(-6)
We add all the numbers together, and all the variables
b-53
Back to the equation:
-(b-53)
-b+53=0
We add all the numbers together, and all the variables
-1b+53=0
We move all terms containing b to the left, all other terms to the right
-b=-53
b=-53/-1
b=+53
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