3=1/3(-6)+b

Solution for 3=1/3(-6)+b equation:

3=1/3(-6)+b

We move all terms to the left:

3-(1/3(-6)+b)=0


Domain of the equation: 3(-6)+b)!=0

b∈R


We multiply all the terms by the denominator


-(1+3*3(-6)+b)=0


We calculate terms in parentheses: -(1+3*3(-6)+b), so:

1+3*3(-6)+b

determiningTheFunctionDomain
b+1+3*3(-6)

We add all the numbers together, and all the variables

b-53

Back to the equation:

-(b-53)


We get rid of parentheses

-b+53=0

We add all the numbers together, and all the variables

-1b+53=0

We move all terms containing b to the left, all other terms to the right

-b=-53

b=-53/-1

b=+53