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3=1/3(10x-12
We move all terms to the left:
3-(1/3(10x-12)=0
Domain of the equation: 3(10x-12)+3!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3(10x-12)!=-3
x∈R
-(1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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