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3=1/3b+5
We move all terms to the left:
3-(1/3b+5)=0
Domain of the equation: 3b+5)!=0We get rid of parentheses
b∈R
-1/3b-5+3=0
We multiply all the terms by the denominator
-5*3b+3*3b-1=0
Wy multiply elements
-15b+9b-1=0
We add all the numbers together, and all the variables
-6b-1=0
We move all terms containing b to the left, all other terms to the right
-6b=1
b=1/-6
b=-1/6
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