3=1/3f(3-3)-5

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Solution for 3=1/3f(3-3)-5 equation: 



3=1/3f(3-3)-5

We move all terms to the left:

3-(1/3f(3-3)-5)=0



Domain of the equation: 3f(3-3)-5)!=0

f∈R



We add all the numbers together, and all the variables

-(1/3f0-5)+3=0

We get rid of parentheses

-1/3f0+5+3=0

We multiply all the terms by the denominator


5*3f0+3*3f0-1=0

Wy multiply elements

15f+9f-1=0

We add all the numbers together, and all the variables

24f-1=0

We move all terms containing f to the left, all other terms to the right

24f=1

f=1/24

f=1/24

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