3=1/4(20q+12)

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Solution for 3=1/4(20q+12) equation:



3=1/4(20q+12)
We move all terms to the left:
3-(1/4(20q+12))=0
Domain of the equation: 4(20q+12))!=0
q∈R
We multiply all the terms by the denominator
-(1+3*4(20q+12))=0
We calculate terms in parentheses: -(1+3*4(20q+12)), so:
1+3*4(20q+12)
determiningTheFunctionDomain 3*4(20q+12)+1
Wy multiply elements
12q(2+1
Back to the equation:
-(12q(2+1)
We add all the numbers together, and all the variables
-(12q3=0

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