3=1/4(20q+12)

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Solution for 3=1/4(20q+12) equation: 



3=1/4(20q+12)

We move all terms to the left:

3-(1/4(20q+12))=0



Domain of the equation: 4(20q+12))!=0

q∈R



We multiply all the terms by the denominator


-(1+3*4(20q+12))=0



We calculate terms in parentheses: -(1+3*4(20q+12)), so:

1+3*4(20q+12)

determiningTheFunctionDomain
3*4(20q+12)+1

Wy multiply elements

12q(2+1

Back to the equation:

-(12q(2+1)



We add all the numbers together, and all the variables

-(12q3=0

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