3=1/5(-5)+b

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Solution for 3=1/5(-5)+b equation: 



3=1/5(-5)+b

We move all terms to the left:

3-(1/5(-5)+b)=0



Domain of the equation: 5(-5)+b)!=0

b∈R



We multiply all the terms by the denominator


-(1+3*5(-5)+b)=0



We calculate terms in parentheses: -(1+3*5(-5)+b), so:

1+3*5(-5)+b

determiningTheFunctionDomain
b+1+3*5(-5)

We add all the numbers together, and all the variables

b-74

Back to the equation:

-(b-74)



We get rid of parentheses

-b+74=0

We add all the numbers together, and all the variables

-1b+74=0

We move all terms containing b to the left, all other terms to the right

-b=-74

b=-74/-1

b=+74

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