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3=1/5-k-2
We move all terms to the left:
3-(1/5-k-2)=0
Domain of the equation: 5-k-2)!=0We add all the numbers together, and all the variables
We move all terms containing k to the left, all other terms to the right
-k-2)!=-5
k∈R
-(-1k+1/5-2)+3=0
We get rid of parentheses
1k+2+3-1/5=0
We multiply all the terms by the denominator
1k*5-1+2*5+3*5=0
We add all the numbers together, and all the variables
1k*5+24=0
Wy multiply elements
5k+24=0
We move all terms containing k to the left, all other terms to the right
5k=-24
k=-24/5
k=-4+4/5
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