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3=12+8/r
We move all terms to the left:
3-(12+8/r)=0
Domain of the equation: r)!=0We add all the numbers together, and all the variables
r!=0/1
r!=0
r∈R
-(8/r+12)+3=0
We get rid of parentheses
-8/r-12+3=0
We multiply all the terms by the denominator
-12*r+3*r-8=0
We add all the numbers together, and all the variables
-9r-8=0
We move all terms containing r to the left, all other terms to the right
-9r=8
r=8/-9
r=-8/9
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