3=12y-5(2y-7)

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Solution for 3=12y-5(2y-7) equation: 



3=12y-5(2y-7)

We move all terms to the left:

3-(12y-5(2y-7))=0



We calculate terms in parentheses: -(12y-5(2y-7)), so:

12y-5(2y-7)

We multiply parentheses

12y-10y+35

We add all the numbers together, and all the variables

2y+35

Back to the equation:

-(2y+35)



We get rid of parentheses

-2y-35+3=0

We add all the numbers together, and all the variables

-2y-32=0

We move all terms containing y to the left, all other terms to the right

-2y=32

y=32/-2

y=-16

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