3=15-2(c-1)-3c

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Solution for 3=15-2(c-1)-3c equation:



3=15-2(c-1)-3c
We move all terms to the left:
3-(15-2(c-1)-3c)=0
We calculate terms in parentheses: -(15-2(c-1)-3c), so:
15-2(c-1)-3c
determiningTheFunctionDomain -2(c-1)-3c+15
We add all the numbers together, and all the variables
-3c-2(c-1)+15
We multiply parentheses
-3c-2c+2+15
We add all the numbers together, and all the variables
-5c+17
Back to the equation:
-(-5c+17)
We get rid of parentheses
5c-17+3=0
We add all the numbers together, and all the variables
5c-14=0
We move all terms containing c to the left, all other terms to the right
5c=14
c=14/5
c=2+4/5

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