3=15-2(c-1)-3c

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Solution for 3=15-2(c-1)-3c equation: 



3=15-2(c-1)-3c

We move all terms to the left:

3-(15-2(c-1)-3c)=0



We calculate terms in parentheses: -(15-2(c-1)-3c), so:

15-2(c-1)-3c

determiningTheFunctionDomain
-2(c-1)-3c+15

We add all the numbers together, and all the variables

-3c-2(c-1)+15

We multiply parentheses

-3c-2c+2+15

We add all the numbers together, and all the variables

-5c+17

Back to the equation:

-(-5c+17)



We get rid of parentheses

5c-17+3=0

We add all the numbers together, and all the variables

5c-14=0

We move all terms containing c to the left, all other terms to the right

5c=14

c=14/5

c=2+4/5

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