3=1r+(-5)

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Solution for 3=1r+(-5) equation: 



3=1r+(-5)

We move all terms to the left:

3-(1r+(-5))=0



We calculate terms in parentheses: -(1r+(-5)), so:

1r+(-5)

We add all the numbers together, and all the variables

r-5

Back to the equation:

-(r-5)



We get rid of parentheses

-r+5+3=0

We add all the numbers together, and all the variables

-1r+8=0

We move all terms containing r to the left, all other terms to the right

-r=-8

r=-8/-1

r=+8

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