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3=2(1/4s-5)+3
We move all terms to the left:
3-(2(1/4s-5)+3)=0
Domain of the equation: 4s-5)+3)!=0We multiply all the terms by the denominator
s∈R
-(2(1+3*4s-5)+3)=0
We calculate terms in parentheses: -(2(1+3*4s-5)+3), so:We get rid of parentheses
2(1+3*4s-5)+3
We add all the numbers together, and all the variables
2(3*4s-4)+3
We multiply parentheses
24s-8+3
We add all the numbers together, and all the variables
24s-5
Back to the equation:
-(24s-5)
-24s+5=0
We move all terms containing s to the left, all other terms to the right
-24s=-5
s=-5/-24
s=5/24
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