3=2(2c+2)-3c

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Solution for 3=2(2c+2)-3c equation: 



3=2(2c+2)-3c

We move all terms to the left:

3-(2(2c+2)-3c)=0



We calculate terms in parentheses: -(2(2c+2)-3c), so:

2(2c+2)-3c

We add all the numbers together, and all the variables

-3c+2(2c+2)

We multiply parentheses

-3c+4c+4

We add all the numbers together, and all the variables

c+4

Back to the equation:

-(c+4)



We get rid of parentheses

-c-4+3=0

We add all the numbers together, and all the variables

-1c-1=0

We move all terms containing c to the left, all other terms to the right

-c=1

c=1/-1

c=-1

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