3=2(3c+7)

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Solution for 3=2(3c+7) equation:



3=2(3c+7)
We move all terms to the left:
3-(2(3c+7))=0
We calculate terms in parentheses: -(2(3c+7)), so:
2(3c+7)
We multiply parentheses
6c+14
Back to the equation:
-(6c+14)
We get rid of parentheses
-6c-14+3=0
We add all the numbers together, and all the variables
-6c-11=0
We move all terms containing c to the left, all other terms to the right
-6c=11
c=11/-6
c=-1+5/6

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