3=2(k-1)-5

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Solution for 3=2(k-1)-5 equation: 



3=2(k-1)-5

We move all terms to the left:

3-(2(k-1)-5)=0



We calculate terms in parentheses: -(2(k-1)-5), so:

2(k-1)-5

We multiply parentheses

2k-2-5

We add all the numbers together, and all the variables

2k-7

Back to the equation:

-(2k-7)



We get rid of parentheses

-2k+7+3=0

We add all the numbers together, and all the variables

-2k+10=0

We move all terms containing k to the left, all other terms to the right

-2k=-10

k=-10/-2

k=+5

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