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3=2+(2)/(x+2)
We move all terms to the left:
3-(2+(2)/(x+2))=0
Domain of the equation: (x+2))!=0We multiply all the terms by the denominator
x∈R
-(2+2+3*(x+2))=0
We calculate terms in parentheses: -(2+2+3*(x+2)), so:We get rid of parentheses
2+2+3*(x+2)
determiningTheFunctionDomain 3*(x+2)+2+2
We add all the numbers together, and all the variables
3*(x+2)+4
We multiply parentheses
3x+6+4
We add all the numbers together, and all the variables
3x+10
Back to the equation:
-(3x+10)
-3x-10=0
We move all terms containing x to the left, all other terms to the right
-3x=10
x=10/-3
x=-3+1/3
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