3=2/10(10)+b

Solution for 3=2/10(10)+b equation:

3=2/10(10)+b

We move all terms to the left:

3-(2/10(10)+b)=0


Domain of the equation: 1010+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-1010

b!=-1010/1

b!=-1010

b∈R


We add all the numbers together, and all the variables

-(+b+2/1010)+3=0

We get rid of parentheses

-b+3-2/1010=0

We multiply all the terms by the denominator


-b*1010-2+3*1010=0

We add all the numbers together, and all the variables

-b*1010+3028=0

Wy multiply elements

-1010b+3028=0

We move all terms containing b to the left, all other terms to the right

-1010b=-3028

b=-3028/-1010

b=2+504/505