3=23(q+4/3)=2

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Solution for 3=23(q+4/3)=2 equation: 



3=23(q+4/3)=2

We move all terms to the left:

3-(23(q+4/3))=0

We add all the numbers together, and all the variables

-(23(+q+4/3))+3=0

We multiply all the terms by the denominator


-(23(+q+4+3*3))=0



We calculate terms in parentheses: -(23(+q+4+3*3)), so:

23(+q+4+3*3)

We add all the numbers together, and all the variables

23(q+13)

We multiply parentheses

23q+299

Back to the equation:

-(23q+299)



We get rid of parentheses

-23q-299=0

We move all terms containing q to the left, all other terms to the right

-23q=299

q=299/-23

q=-13

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