3=2x2-4x

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Solution for 3=2x2-4x equation:



3=2x^2-4x
We move all terms to the left:
3-(2x^2-4x)=0
We get rid of parentheses
-2x^2+4x+3=0
a = -2; b = 4; c = +3;
Δ = b2-4ac
Δ = 42-4·(-2)·3
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{10}}{2*-2}=\frac{-4-2\sqrt{10}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{10}}{2*-2}=\frac{-4+2\sqrt{10}}{-4} $

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