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3=3(2x-3)/x+1
We move all terms to the left:
3-(3(2x-3)/x+1)=0
Domain of the equation: x+1)!=0We multiply all the terms by the denominator
x∈R
-(3(2x-3)+3*x+1)=0
We calculate terms in parentheses: -(3(2x-3)+3*x+1), so:We get rid of parentheses
3(2x-3)+3*x+1
We add all the numbers together, and all the variables
3x+3(2x-3)+1
We multiply parentheses
3x+6x-9+1
We add all the numbers together, and all the variables
9x-8
Back to the equation:
-(9x-8)
-9x+8=0
We move all terms containing x to the left, all other terms to the right
-9x=-8
x=-8/-9
x=8/9
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