3=3(c-2)-5(2c+1)

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Solution for 3=3(c-2)-5(2c+1) equation:


Simplifying
3 = 3(c + -2) + -5(2c + 1)

Reorder the terms:
3 = 3(-2 + c) + -5(2c + 1)
3 = (-2 * 3 + c * 3) + -5(2c + 1)
3 = (-6 + 3c) + -5(2c + 1)

Reorder the terms:
3 = -6 + 3c + -5(1 + 2c)
3 = -6 + 3c + (1 * -5 + 2c * -5)
3 = -6 + 3c + (-5 + -10c)

Reorder the terms:
3 = -6 + -5 + 3c + -10c

Combine like terms: -6 + -5 = -11
3 = -11 + 3c + -10c

Combine like terms: 3c + -10c = -7c
3 = -11 + -7c

Solving
3 = -11 + -7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '7c' to each side of the equation.
3 + 7c = -11 + -7c + 7c

Combine like terms: -7c + 7c = 0
3 + 7c = -11 + 0
3 + 7c = -11

Add '-3' to each side of the equation.
3 + -3 + 7c = -11 + -3

Combine like terms: 3 + -3 = 0
0 + 7c = -11 + -3
7c = -11 + -3

Combine like terms: -11 + -3 = -14
7c = -14

Divide each side by '7'.
c = -2

Simplifying
c = -2

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