3=3/5(2)+b

Solution for 3=3/5(2)+b equation:

3=3/5(2)+b

We move all terms to the left:

3-(3/5(2)+b)=0


Domain of the equation: 52+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-52

b!=-52/1

b!=-52

b∈R


We add all the numbers together, and all the variables

-(+b+3/52)+3=0

We get rid of parentheses

-b+3-3/52=0

We multiply all the terms by the denominator


-b*52-3+3*52=0

We add all the numbers together, and all the variables

-b*52+153=0

Wy multiply elements

-52b+153=0

We move all terms containing b to the left, all other terms to the right

-52b=-153

b=-153/-52

b=2+49/52