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3=3/5(b-8)
We move all terms to the left:
3-(3/5(b-8))=0
Domain of the equation: 5(b-8))!=0We multiply all the terms by the denominator
b∈R
-(3+3*5(b-8))=0
We calculate terms in parentheses: -(3+3*5(b-8)), so:
3+3*5(b-8)
determiningTheFunctionDomain 3*5(b-8)+3
Wy multiply elements
15b(b+3
Back to the equation:
-(15b(b+3)
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| 9^{3x+4}=1/9 | | 5/6y+1=-13y+4/9 | | 56y+1=−13y+49; | | x*(3*x)=90 | | 3(x+4)=2(-2x+11) | | 1+6x=19+3x | | 2a-4-2a=-4 | | 1/x=1/5x-x-1/ | | x-8=-15/x | | 95=38+(8m+4) | | 6x − 39 = 3x − 21 | | 3(2y-4)=2(3y+4) | | 42+5t=8=8t | | 42=-2v+14 | | 4(y-11)-(y-8)=0 | | (5x+4)=(3x-2) | | (y-11)-(y+8)=0 | | 4x − 134 = 38x − 18 | | 65=-13(-7+v) | | 10x-1,+6x+5,+6x+5,+8x+9,+8x+9=540 | | 26-4v=2 | | 13y=65×2 | | -10(v+11)=-90 | | 22=b^2 | | 4x-9=4x-12 | | -5c-10=4c-10+9c | | 10+4u=-6+6u | | 18x-35+5x²=0 | | -4g-2-7g=8-10g | | -10-8-5m=-8m+9 | | 10+6h=3+7h | | 6-9h=8-10h |