3=3/5(c-1)

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Solution for 3=3/5(c-1) equation: 



3=3/5(c-1)

We move all terms to the left:

3-(3/5(c-1))=0



Domain of the equation: 5(c-1))!=0

c∈R



We multiply all the terms by the denominator


-(3+3*5(c-1))=0



We calculate terms in parentheses: -(3+3*5(c-1)), so:

3+3*5(c-1)

determiningTheFunctionDomain
3*5(c-1)+3

Wy multiply elements

15c(c+3

Back to the equation:

-(15c(c+3)





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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15c(c+3





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