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3=3/5(c-1)
We move all terms to the left:
3-(3/5(c-1))=0
Domain of the equation: 5(c-1))!=0We multiply all the terms by the denominator
c∈R
-(3+3*5(c-1))=0
We calculate terms in parentheses: -(3+3*5(c-1)), so:
3+3*5(c-1)
determiningTheFunctionDomain 3*5(c-1)+3
Wy multiply elements
15c(c+3
Back to the equation:
-(15c(c+3)
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| 5y=4y+6-y | | −2(y+4)=28 | | 1=x/3=3 | | -7+x/5=-7 | | x2–99=0 | | 2+1/x=1/x-2 | | 5x-6=3x-6-2x | | 1/50w=2 | | 3(x-2)^2-12=0 | | 1/4(20-4a)=6-4 | | 135=-1+45x=23x | | 7-(-6x-2)=27 | | 2z=2z−1 | | 5c=-8+5c | | 4×-9=k | | -5+x/8=2x | | 38=2x+125=x+163 | | 146+2x=172=2x+26 | | -9r+3=6r+93 | | 7x+9=2(x-3) | | 2(r+2)=14 | | 9u+9=9 | | 6b-546=-6 | | (5x-6)×4=1×3 | | (5x-6)×4=(1+x)×3 | | 3(x-5)-2=7 | | 175=17x-3=17x+8 | | -28=-3+5y | | 5(6+x)=4x | | m^2=25/49 | | x=x-34 | | 9y+7=(2y+98) |