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3=5(x-1)+5-4x
We move all terms to the left:
3-(5(x-1)+5-4x)=0
We calculate terms in parentheses: -(5(x-1)+5-4x), so:We add all the numbers together, and all the variables
5(x-1)+5-4x
determiningTheFunctionDomain 5(x-1)-4x+5
We add all the numbers together, and all the variables
-4x+5(x-1)+5
We multiply parentheses
-4x+5x-5+5
We add all the numbers together, and all the variables
x
Back to the equation:
-(x)
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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