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3=5/9(x-32)
We move all terms to the left:
3-(5/9(x-32))=0
Domain of the equation: 9(x-32))!=0We multiply all the terms by the denominator
x∈R
-(5+3*9(x-32))=0
We calculate terms in parentheses: -(5+3*9(x-32)), so:
5+3*9(x-32)
determiningTheFunctionDomain 3*9(x-32)+5
Wy multiply elements
27x(x+5
Back to the equation:
-(27x(x+5)
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| -42=(6x-6) | | -8=-13x-65 | | 3x2+4x=5/2x+9 | | 0.09h+13.29=0.16h+14.04 | | 3x-4=6-(-2x) | | d+12.1=38.2 | | 12x+9=41 | | r+7=14-6r | | s*4+35=135 | | 5n-9=6n-7 | | 6q=+7+-10q | | 8369x+x=5 | | -5x-5+4x=-7 | | -4w+40=-6(w-6) | | M^2-2=m | | 7n^2=-56+63n | | 7-4y=2y+8 | | 1x=(9/8) | | 9z−7=10z | | −t+5=t−19 | | 2(v-4)+3v=-13 | | -27=5x+3(x+7) | | -6x2+23x+4=0 | | -75x+57=−75x+57 | | 7k+1=120 | | 75x+57=−75x+57 | | (5a+4)(a-6)=0 | | 3(x+1)-6(x-5)=3 | | 2d=1/5=3/5 | | -(3/4)x+1=-11 | | 2m+1=3(m-18 | | y=2(6+y)+6 |