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3=5y(8+1/5y)
We move all terms to the left:
3-(5y(8+1/5y))=0
Domain of the equation: 5y))!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-(5y(1/5y+8))+3=0
We multiply all the terms by the denominator
-(5y(1+3*5y+8))=0
We calculate terms in parentheses: -(5y(1+3*5y+8)), so:We get rid of parentheses
5y(1+3*5y+8)
We add all the numbers together, and all the variables
5y(3*5y+9)
We multiply parentheses
75y^2+45y
Back to the equation:
-(75y^2+45y)
-75y^2-45y=0
a = -75; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·(-75)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*-75}=\frac{0}{-150} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*-75}=\frac{90}{-150} =-3/5 $
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