3=7(c-2)+17

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Solution for 3=7(c-2)+17 equation: 



3=7(c-2)+17

We move all terms to the left:

3-(7(c-2)+17)=0



We calculate terms in parentheses: -(7(c-2)+17), so:

7(c-2)+17

We multiply parentheses

7c-14+17

We add all the numbers together, and all the variables

7c+3

Back to the equation:

-(7c+3)



We get rid of parentheses

-7c-3+3=0

We add all the numbers together, and all the variables

-7c=0

c=0/-7

c=0

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