3=7(h-2)+1

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Solution for 3=7(h-2)+1 equation: 



3=7(h-2)+1

We move all terms to the left:

3-(7(h-2)+1)=0



We calculate terms in parentheses: -(7(h-2)+1), so:

7(h-2)+1

We multiply parentheses

7h-14+1

We add all the numbers together, and all the variables

7h-13

Back to the equation:

-(7h-13)



We get rid of parentheses

-7h+13+3=0

We add all the numbers together, and all the variables

-7h+16=0

We move all terms containing h to the left, all other terms to the right

-7h=-16

h=-16/-7

h=2+2/7

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