3=7(k-2)=17

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Solution for 3=7(k-2)=17 equation: 



3=7(k-2)=17

We move all terms to the left:

3-(7(k-2))=0



We calculate terms in parentheses: -(7(k-2)), so:

7(k-2)

We multiply parentheses

7k-14

Back to the equation:

-(7k-14)



We get rid of parentheses

-7k+14+3=0

We add all the numbers together, and all the variables

-7k+17=0

We move all terms containing k to the left, all other terms to the right

-7k=-17

k=-17/-7

k=2+3/7

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