3=7/2(3x+4)

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Solution for 3=7/2(3x+4) equation: 



3=7/2(3x+4)

We move all terms to the left:

3-(7/2(3x+4))=0



Domain of the equation: 2(3x+4))!=0

x∈R



We multiply all the terms by the denominator


-(7+3*2(3x+4))=0



We calculate terms in parentheses: -(7+3*2(3x+4)), so:

7+3*2(3x+4)

determiningTheFunctionDomain
3*2(3x+4)+7

Wy multiply elements

6x(3+7

Back to the equation:

-(6x(3+7)



We add all the numbers together, and all the variables

-(6x10=0

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