3=c-47/10

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Solution for 3=c-47/10 equation: 



3=c-47/10

We move all terms to the left:

3-(c-47/10)=0

We add all the numbers together, and all the variables

-(+c-47/10)+3=0

We get rid of parentheses

-c+3+47/10=0

We multiply all the terms by the denominator


-c*10+47+3*10=0

We add all the numbers together, and all the variables

-c*10+77=0

Wy multiply elements

-10c+77=0

We move all terms containing c to the left, all other terms to the right

-10c=-77

c=-77/-10

c=7+7/10

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