3=k-62/7

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Solution for 3=k-62/7 equation: 



3=k-62/7

We move all terms to the left:

3-(k-62/7)=0

We add all the numbers together, and all the variables

-(+k-62/7)+3=0

We get rid of parentheses

-k+3+62/7=0

We multiply all the terms by the denominator


-k*7+62+3*7=0

We add all the numbers together, and all the variables

-k*7+83=0

Wy multiply elements

-7k+83=0

We move all terms containing k to the left, all other terms to the right

-7k=-83

k=-83/-7

k=11+6/7

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