3=k2+8

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Solution for 3=k2+8 equation: 



3=k2+8

We move all terms to the left:

3-(k2+8)=0

We add all the numbers together, and all the variables

-(+k^2+8)+3=0

We get rid of parentheses

-k^2-8+3=0

We add all the numbers together, and all the variables

-1k^2-5=0

a = -1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-5)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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