3=n-79/6

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Solution for 3=n-79/6 equation: 



3=n-79/6

We move all terms to the left:

3-(n-79/6)=0

We add all the numbers together, and all the variables

-(+n-79/6)+3=0

We get rid of parentheses

-n+3+79/6=0

We multiply all the terms by the denominator


-n*6+79+3*6=0

We add all the numbers together, and all the variables

-n*6+97=0

Wy multiply elements

-6n+97=0

We move all terms containing n to the left, all other terms to the right

-6n=-97

n=-97/-6

n=16+1/6

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