3=y-4/x

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Solution for 3=y-4/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3 = y-(4/x) // - y-(4/x)

4/x-y+3 = 0

4*x^-1 = -(3-y) // : 4

x^-1 = (y-3)/4

-1 < 0

1/(x^1) = (y-3)/4 // * x^1

1 = x^1*((y-3)/4) // : (y-3)/4

4*(y-3)^-1 = x^1

x = 4*(y-3)^-1

x = 4*(y-3)^-1

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