3=z+129

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Solution for 3=z+129 equation: 



3=z+129

We move all terms to the left:

3-(z+129)=0

We get rid of parentheses

-z-129+3=0

We add all the numbers together, and all the variables

-1z-126=0

We move all terms containing z to the left, all other terms to the right

-z=126

z=126/-1

z=-126

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