3I2x+5I=12

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Solution for 3I2x+5I=12 equation: 



32I+5=12

We move all terms to the left:

32I+5-(12)=0

We add all the numbers together, and all the variables

32I-7=0

We move all terms containing I to the left, all other terms to the right

32I=7

I=7/32

I=7/32

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